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2 years ago

2/3 rational or irrational

Mathematics

1 answer:

MatroZZZ [7]2 years ago

4 0

Rational numbers is the answer

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3) Last year Kerry’s take home pay was £15 000 She spent 40% of her take home pay on rent. She used the rest of her take home pa

gregori [183]

3,000. You take 15,000 and multiply by .4 to get how much she spent on rent (6,000). They you subtract the rent money from her total pay to get her money that she spent on living expenses, clothes and entertainment in total (9,000). Since she spent her money in six parts (3+2+1), you divide 9,000 by 6 to get 1,500 to get each part. Since for entertainment she has two parts you multiply 1,500 by 2 to get 3,000.

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2 years ago

What is the image of A under the translation described by the translation rule (x, y)--->(x + 4, y - 10)?

Mademuasel [1]

Translation rule (x, y)--->(x + 4, y - 10)

Object A = (5, 6)

Apply rule:

(5, 6)---->(5 + 4, 6 - 10) = (9, -4)

Image A' = (9, -4)

Option 3: (9, -4) is the answer

6 0

2 years ago

A book publishing company is shipping an order of 300 books.the books are packaged in boxes that each can hold 24 books.how many

ryzh [129]

300/24=12 your answer would be 12

4 0

3 years ago

I need help on math hw

dolphi86 [110]

Answer:

which part do u need go in and what grade is this work on

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2 years ago

Match its group with its percentage or mean Using

krok68 [10]

(1)

Mean length of all fish in the sample - $\boxed{\sf{\red{6.2}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

= 6.2

(2)

Mean length of adult fish in the sample - $\boxed{\sf{\red{8.75}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

= 8.75

(3)

Mean length of juvenile fish in the sample - $\boxed{\sf{\red{4.5}}}$

Mean = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

= 4.5

(4)

Percentage of sample that were adult fish - $\boxed{\sf{\red{40}}}$

Percentage = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

% = 40

(5)

Percentage of sample that were juvenile fish - $\boxed{\sf{\red{60}}}$

Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

% = 60

(6)

Percentage of sample that were juveniles over 8 inches long - $\boxed{\sf{\red{10}}}$

Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

% = 10

7 0

2 years ago