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2 years ago

Double a number decreased by 4

Mathematics

2 answers:

tatuchka [14]2 years ago

4 0

Answer:

Well, if you are doubling a number with a product that can be decreased by 4 to go back to your original number, the answer to your question is 8.

Step-by-step explanation:

(4)(2 : double) = 8

8 - 4 = 4 (original number)

Wittaler [7]2 years ago

3 0

Answer:

2x-5 if u want u can substitute any other variables and constant

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Given that x square + 5 x + c is a perfect square find the value of C

lawyer [7]

Answer:

c = $\frac{25}{4}$

Step-by-step explanation:

To make a perfect square

add ( half the coefficient of the x- term )² to x² + 5x

x² + 5x + ( $\frac{5}{2}$ )²

= x² + 5x + $\frac{25}{4}$

= (x + $\frac{5}{2}$ )² ← a perfect square

5 0

3 years ago

Complete this statement:

klasskru [66]

Answer:

$45x^3a+27xa^2= 9xa(5x^2+3a)$

Step-by-step explanation:

Given:

$45x^3a+27xa^2= 9xa$

We need to complete this Statement.

By Solving the above equation we get;

We will take some common factor out so we will get;

$45x^3a+27xa^2= 9xa(5x^2+3a)$

Hence the Complete statement is $45x^3a+27xa^2= 9xa(5x^2+3a)$

5 0

3 years ago

Pls need help!!!! Giving brainliest to the person that gives me the right awnser

jeka57 [31]

Answer:

you only have the answer choices not the question itself

could you please attach the question so i can help?

6 0

3 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$