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Doss [256]
3 years ago
15

PLEASE HELP ASAP

Mathematics
1 answer:
zaharov [31]3 years ago
4 0
Wouldn’t it be 0, as that’s when their values are both equal to each other, making the equation true?
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The veterinarlan told Sally that her cat needs to lose 5 pounds. A healthy weight loss for her cat would be about 1 pound every
padilas [110]

Answer:

It would take 10 weeks for her cat to lose 5 pounds.

Step-by-step explanation:

4 0
2 years ago
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I need help for all of this problems!
Harlamova29_29 [7]
A) All triangles add up to 180° so when given two angles, add those up and subtract them from 180° . That will give you the missing angle.

3-5) When you do A above, and receive the measurement of angle 1, it will also equal 2 and you can repeat A for missing angle 3

6-8) Find the missing angle next to 1, and then subtract that from 180°. That number is the answer for 1. 2 is 55 as its a complimentary (i think thats the right term) angle. Which means it is on the opposite side of an angle. I don't remember how to find 3 however, its been a few years since I've done triangles.
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3 years ago
Select the factors of 10ax 5bx − 8ay − 4by.
Yakvenalex [24]
10ax + 5bx - 8ay - 4by = 5x(2a + b) - 4y(2a + b) = (5x - 4y)(2a + b)
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4 0
3 years ago
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When you translate a finger left does the x-or y-coordinates change
Damm [24]
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6 0
3 years ago
Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

7 0
2 years ago
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