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Arisa [49]
3 years ago
10

James put $1000 in a 2-year CD paying 7% interest, compounded monthly.

Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer with explanation:

Principal = $ 1000

Time = 2 years

Rate of Interest = 7 %

Since of rate of interest is compounded monthly,

then, R=\frac{7}{12}\\\\T=2 \times 12 =24

Amount after 2 years

 =P\times [1 +\frac{R}{100}]^T\\\\=1000 \times [1+\frac{7}{1200}]^{24}\\\\=1000 \times [\frac{1207}{1200}]^{24}\\\\=1000 \times (1.00583)^{24}\\\\=1000\times 1.14972\\\\=1149.72

Amount after 2 years, when rate of interest, is compounded monthly=$ 1149.72  

ruslelena [56]3 years ago
4 0
To find the future value of this investment the formula is
A=p (1+r/k)^kt
A future value?
P present value 1000
R interest rate 0.07
K compounded monthly 12
T time 2 years
A=1,000×(1+0.07÷12)^(12×2)
A=1,149.81
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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
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As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
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\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

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3 years ago
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