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3 years ago

Helpppppp solve it find the area please

Mathematics

1 answer:

natulia [17]3 years ago

5 0

One way is to find the area of the shape as if it was a whole square instead of an H shape.

That is (125+75+125) x (345), which is 112125 ft^2.

From this, let's subtract the areas of the cut-outs.

The cutouts are squares and both the same size. One side of it is 112 feet, so the area of one is 112x112=12544. So, the two squares have an area of 25088.

Now subtract that from the original total. 112125-25088=87037. <<that is the area.

You might want to double check my work.

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3 years ago

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3 years ago

Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min, and its coarseness is such that it forms a pile in the shap

ikadub [295]

The height is increasing at the rate of (6/5π) ft/min.

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2 years ago

ACBM is a segment of a circle such

tatiyna

Answer:

a. 8.94 cm b. 127° c. 12.37 cm²

Step-by-step explanation:

a. Since CM = 4 cm is the perpendicular bisector of AB = 16 cm and r is the radius off the circle. From Pythagoras' theorem,

r² = (AB/2)² + CM²

r = √[(AB/2)² + CM²]

Substituting the values of the variables into r, we have

r = √[(16/2)² + 4²]

r = √[8² + 4²]

r = 4√[2² + 1²]

r = 4√[4 + 1]

r = 4√5 cm

r = 8.94 cm

b. We know that the length of a chord L = 2rsin(θ/2) where r is the radius of the circle, and θ is the angle subtended by the chord AB.

Since L = 2rsin(θ/2) and L = AB = 16 cm,

L/2r = sin(θ/2)

taking sine inverse of both sides, we have

θ/2 = sin⁻¹(L/2r)

multiplying both sides by 2, we have

θ = 2sin⁻¹(L/2r)

substituting the values of the variables, we have

θ = 2sin⁻¹[16/(2 × 8.94)]

θ = 2sin⁻¹[16/17.88]

θ = 2sin⁻¹[0.8949]

θ = 2 × 63.49°

θ = 126.98°

θ ≅ 127°

c. The area of a segment A is given by

A = (θπ/360 - sinθ)r²/2 where θ is the angle subtended by the segment and r = radius of the circle

since θ ≅ 127° and r = 4√5 cm, substituting these values into A, we have

A = (127°π/360 - sin127°)(4√5)²/2

A = (398.93/360 - 0.7988)40

A = (1.1081 - 0.7988)40

A = 0.3093 × 40

A = 12.372 cm²

A ≅ 12.37 cm²

5 0

3 years ago