The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
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Answer:
Step-by-step explanation:
<u>The roots are:</u>
- 3, 3, 2 - 3i, 2 + 3i (conjugate of 2 - 3i should be added) and the leading coefficient is - 5
<u>The polynomial is:</u>
- -5(x - 3)² (x - [2 - 3i]) (x - [2 + 3i]) =
- - 5(x² - 6x + 9) (x² - 4x + 13) =
- -5(x⁴ - 10x³ + 46x² - 114x + 117) =
- -5x⁴ + 50x³ - 230x² + 570x - 585
Step-by-step explanation:
If there's a number that has for example 6/5 the / means dividing
Answer:
$50.83
Step-by-step explanation:
44.20 x .15 = 6.63
44.20 + 6.63= 50.83
Sin(2x)-sin(4x)=0
-2cos(3x)sin(x)=0
x=pi/6+2kpi/3
x=pi/2+2kpi/3, k=no solution
x=2kpi
x=pi+2kpi