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Montano1993 [528]
3 years ago
12

DETERMINE THE MEASURE

Mathematics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

I have no idea sorry for wasting your time

Step-by-step explanation:

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Sari wrote the equivalent ratios below to convert cups to fluid ounces. StartFraction 8 fluid ounces Over 1 cup EndFraction = St
Amiraneli [1.4K]

Answer:

(B)72 fluid ounces

Step-by-step explanation:

To convert cups to fluid ounces, Sari wrote the equivalent ratios.

\dfrac{8 \text{ fluid ounces}}{1\text{ cup}} =\dfrac{\text{? fluid ounces}}{9\text{ cups}}

Let the question mark be represented by x.

We then have:

\dfrac{8 \text{ fluid ounces}}{1\text{ cup}} =\dfrac{\text{x fluid ounces}}{9\text{ cups}}\\$Cross multiply\\x \times 1 = 8 \times 9\\x=72$ fluid ounces

We conclude that there are 72 fluid ounces in 9 cups.

7 0
3 years ago
Read 2 more answers
What is the midpoint of the segment shown below?
Aneli [31]

Answer:

(1, -3/2)

Step-by-step explanation:

The x coordinate is the same for both endpoints so the x coordinate for the midpoint is 1

The y coordinate for the midpoint is found by adding the two y coordinates and dividing by 2

(2+-5)/2 = -3/2

The midpoint is

(1, -3/2)

5 0
3 years ago
Read 2 more answers
A) Write a rule for a polynomial with left end up and right end up behavior, and has a y-
Novosadov [1.4K]

Answer:

y = x^2 + 3

Step-by-step explanation:

The equation I put has the left end up, the right end up, and has a y-intercept at (0,3).

If this answer is correct, please make me Brainliest!

7 0
3 years ago
Find the equation of a line with the given points. 7, 3 , 5, -1
MissTica

Answer:

i think if its on a graph

Step-by-step explanation:

5 0
3 years ago
Find the sixth term of the geometric sequence<br> 9, 18, 36, ...
timama [110]

Answer:

This is a geometric sequence because any term divided by the previous term is a constant called the common ratio. r=36/18=18/9=2 A geometric sequence is expressed as

\begin{gathered}a_n=ar^{n-1},\text{ where a=initial term, r=common ratio, n=term number}\\ \\ a_n=9(2^{n-1})\\ \\ a_6=9(2^5)\\ \\ a_6=288\end{gathered}an=arn−1, where a=initial term, r=common ratio, n=term numberan=9(2n−1)a6=9(25)a6=288

6 0
3 years ago
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