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Lelu [443]
3 years ago
7

What is the vertex of the graph shown below? Write your answer in the form (x,y)

Mathematics
1 answer:
charle [14.2K]3 years ago
7 0
The vertex of a parabola is the point where the parabola crosses its axis of symmetry.
 For this case we have that the vertex of the parabola is the point:
 (x, y) = (1, 4)
 Equivalently:
 x = 1
 y = 4
 answer:
 the vertex of the graph shown below is 
 (x, y) = (1, 4)
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mote1985 [20]

Answer:

12 ounces

Step-by-step explanation:

.17×12=2.04

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3 years ago
What is the coefficient of x^2 in the expansion of (x+2)^3
goldenfox [79]
(x+2)^3=x^3+2^3+3*x^2*2+3x*2^2=x^3+8+6x^2+12x

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3 0
3 years ago
The vertical angle to the top of a flagpole from point A on the ground is observed to be 37°11'. The observer walks 17 m directl
inysia [295]

Answer:

22m

Step-by-step explanation:

Let height of flagpole=h

AB==17 m

\angle CAD=37^{\circ}11'=37+\frac{11}{60}=37.183^{\circ}(1 degree= 60 minute)

\angle B=25^{\circ}43'=25+\frac{43}{60}=25.72^{\circ}

We have to find the approximate height of the flagpole.

In triangle CDA,

\frac{CD}{DA}=tan\theta=\frac{Perpendicular\;side}{Base}

\frac{h}{DA}=tan37.183^{\circ}

h=DA(0.759)

In triangle CDB,

tan 25.72^{\circ}=\frac{CD}{DB}

0.482=\frac{h}{DA+17}

0.482DA+8.194=h

Substitute the value

0.482DA+8.194=0.759DA

8.194=0.759DA-0.482DA

8.194=0.277DA

DA=\frac{8.194}{0.277}=29.58

Substitute the value

h=29.58 \times 0.759=22.45 m\approx 22m

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3 0
3 years ago
7 video games for $188.88. How much per game?<br> answer ASAP
Jet001 [13]

Answer:

but it might not be direct

26

Step-by-step explanation:

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6 0
3 years ago
What is the vertex of the function f(x) = one-halfx2 + 3x + three-halves?
Morgarella [4.7K]

Answer:

The vertex of the function is (-3 , -3)

Step-by-step explanation:

* Lets explain how to find the vertex of the quadratic function

- The general form of the quadratic function is f(x) = ax² + bx + c,

  where a , b , c are constant

- The vertex of the quadratic function is (h , k) , where

  h = -b/2a and k = f(h)

* Lets solve the problem

∵ f(x) = one-half x² + 3x + three-halves

∴ f(x) = 1/2 x² + 3x + 3/2

∵ f(x) = ax² + bx + c

∴ a = 1/2 , b = 3 , c = 3/2

∵ The coordinates of its vertex is (h , k)

∵ h = -b/2a

∴ h = -3/2(1/2) = -3/1 = -3

∴ h = -3

∵ k = f(h)

∴ k = f(-3)

∵ f(-3) = 1/2 (-3)² + 3(-3) + 3/2 = -3

∴ k = -3

∴ The vertex of the function is (-3 , -3)

5 0
3 years ago
Read 2 more answers
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