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Margarita [4]
3 years ago
8

A daycare charges a base fee of 3 dollars plus 0.50 dollars per minute for late (after closing time) pick-ups. Albin had to pay

10.50 dollars for a late pick-up. Albin uses the equation, 10.50 = 0.50 a + 3 to represent the situation. What does the variable a represent in the equation?
Mathematics
2 answers:
Talja [164]3 years ago
6 0

Answer:

<h2>The time in minutes for late pick ups</h2>

Step-by-step explanation:

Given the expression for the situation

10.50 = 0.50 a + 3

The variable "a" represents the time in minutes for late pick ups.

The expression is similar to the equation of a straight line

y=mx+c    

when compared to the given expression

we can state that

y= 10.5 which is the outcome of the situation

m= gradient which is 0.5

a= independent variable which is the time in minutes

c= 3 which is the constant term

Sophie [7]3 years ago
5 0

Answer:

a or number of minutes of pickups

Step-by-step explanation:

khan

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Using y=mx+b find the slope for<br> 7) 8x + 3y = −9
malfutka [58]

Answer:

-8/3

Step-by-step explanation:

8x + 3y = - 9

Let's make y the subject of the formula.

y = - 9/3 - 8x/3

Rearrange

y = - 8x/3 - 3

The slope is the coefficient of x which is - 8/3

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7 0
2 years ago
The general form of an parabola is 2x2−12x−3y+12=0 .
Murljashka [212]

Answer:

The standard form of the parabola is (x-3)^2=4*\frac{3}{8}(y+2)

Step-by-step explanation:

The standard form of a parabola is

(x-h)^2=4p(y-k).

In order to convert 2x^2-12x-3y+12=0 into the standard form, we first separate the variables:

2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y

we now divided both sides by 2 to remove the coefficient from 2x^2 and get:

x^2-6x+6=\frac{3}{2}y.

We complete the square on the left side by adding 3 to both sides:

x^2-6x+6+3=\frac{3}{2}y+3

x^2-6x+9=\frac{3}{2}y+3

(x-3)^2=\frac{3}{2}y+3

now we bring the right side into the form 4p(y-k) by first multiplying the equation by \frac{2}{3}:

\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2

and then we multiplying both sides by \frac{3}{2} to get

(x-3)^2=\frac{3}{2} (y+2).

Here we see that

4p=\frac{3}{2}

\therefore p=\frac{3}{8}

Thus, finally we have the equation of the parabola in the standard form:

\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}

5 0
3 years ago
PLEASEEEE I NEED HELP!!!!<br> Find k in the following arithmetic sequence:<br> 4k-k^2, 3k, k
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k = -5.5
3 0
3 years ago
I need help with dis plz
kkurt [141]
Y = -3x + 10
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6 0
2 years ago
3x-7y=-28 Need help solving the question
Valentin [98]
P.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px 'Helvetica Neue'; color: #454545} p.p2 {margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px 'Helvetica Neue'; color: #454545; min-height: 14.0px}

Simplifying

3x + 7y = 28


Solving

3x + 7y = 28


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Add '-7y' to each side of the equation.

3x + 7y + -7y = 28 + -7y


Combine like terms: 7y + -7y = 0

3x + 0 = 28 + -7y

3x = 28 + -7y


Divide each side by '3'.

x = 9.333333333 + -2.333333333y


Simplifying

x = 9.333333333 + -2.333333333y

7 0
3 years ago
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