Answer:
-2
Step-by-step explanation:
g(3)= 2(3)-7
g(3)= 6-7
g(3)= -1
f(g(3))= 4(-1)+2
f(g(3))= -4+2
f(g(3))= -2
Answer:
I think it should be 5y+24
Answer:
d = 5,35 ft
Step-by-step explanation: See annex
Figure in annex is clear,
sin ∠42⁰ = d / 8
And
sin ∠42⁰ = 0.669
d/8 = 0,669
d = 0,669*8
d = 5,35 ft
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.
Let us find z-score of data point 22.03.
Using probability formula 
, we will get:
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
To answer this item, we make use of the equation derive from the Pythagorean theorem for right triangles which states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the two shorter sides. If we let x be the measure of both the shorter sides (we call this as legs), we have,
(14 in)² = (x²) + (x²)
Simplifying the equation,
196 in² = 2x²
Divide both sides of the equation by 2,
98 in² = x²
To get the value of x, we get the square root of both sides of the equation,
x = sqrt (98) = 7√2 inches
Hence, the measure of each leg of the right triangle is 7√2 inches or approximately 9.9 inches.
