2 because the equation can be reduced to: 8.0 x 10^4.
Okay, so 2/3 minus 2/3 would equal to 0. hope this helps :)
3 hours
You can turn this into an equation:
F = 26 + 31t
Where F is the money Ralph earned, and t is the number of hours he worked.
Plugging in the 119 for F, we get
119 = 26 + 31t
93 = 31t
3 = t
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
1. 16
2. 12
3. 0
4. 17
5. 16
6. 4
7. 32
8. 36
9. 1/18
Step-by-step explanation: