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4 years ago

What is the speed of a car that travels 60 meters in 5 seconds

Physics

1 answer:

Karolina [17]4 years ago

3 0

Answer:

60 ÷ 5= 12 is the speed, hope it helps

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A tall cylinder contains 25 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t

Fed [463]

Answer: $377.3\ kPa$

Explanation:

Given

Water column height $h=25\ cm$

After oil is poured, the total height becomes $h'=40\ cm$

Pressure at the bottom will be the sum due to the water and oil column

Suppose the density of the oil is $\rho=900\ kg/m^3$

Pressure at the bottom

$\Rightarrow P=10^3\times g\times 25+900\times g\times 15\\\Rightarrow P=100g[250+135]\\\Rightarrow P=3773\times 100\ Pa\\\Rightarrow P=377.3\ kPa$

4 0

3 years ago

Steam enters a long, horizontal pipe with an inlet diameter of D1 = 16 cm at 2 MPa and 300°C with a velocity of 2.5 m/s. Farther

polet [3.4K]

Answer:

m = 0.4005 kg/s

Q_out = 45.1 KJ/s

Explanation:

Given

Pipe inlet diameter D1 = 16 cm

Steam inlet pressure P1 = 2 Mpa

Steam inlet temperature T1 = 300 °C

Pipe outlet diameter D2 = 14 cm

Steam inlet velocity V1 = 2.5 m/s

Steam outlet pressure P2 = 1.8 MPa

Steam outlet temperature T2 = 250 °C

Required

Determine

(a) The mass flow rate of steam.

(b) The rate of heat transfer.

Assumptions

Kinetic and potential energy changes are negligible.

This is a steady flow process.

There is no work interaction.

Solution

Part a From steam table (A-6) at P1 = 2 Mpa , T1 = 300 °C

vl = 0.12551 m^3/Kg

h1 = 3024.2 KJ/Kg

The mass flow rate of steam could be defined as the following

m = 1/v1*A1*V1

m = 0.4005 kg/s

Part b We take the pipe as our system.The energy balance could be defined as the following

E_in -E_out =ΔE_sys = 0

E_in = E_out

mh_1 = Q_out + mh_2

Q_out = m(h_1-h_2)

From steam table (A-6) at P2= 1.8 Mpa T2 = 250 °C h2= 2911.7 KJ/Kg The heat transfer could be defined as the following

Q_out = m(h_1-h_2)

Q_out = 0.4005*(3024.2 -2911.7) =45.1 KJ/s

6 0

3 years ago

The moon has a mass of 7.35x1022 kg and is a lot farther away than is shown in textbooks. The mass of the

anyanavicka [17]

Answer:

$F=1.98\times 10^{20}\ N$

Explanation:

Given that,

The mass of a Moon, $M_m=7.35\times 10^{22}\ kg$

The mass of the Earth, $M_e=5.98\times 10^{24}\ kg$

The moon's mean orbit distance around the earth is, $r=3.84\times 10^8\ m$

We need to find the gravitational force exerted on the moon by the Earth.

The formula of gravitational force is given by :

$F=G\dfrac{M_mM_e}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{7.35\times 10^{22}\times 5.98\times 10^{24}}{(3.84\times 10^8)^2}\\\\F=1.98\times 10^{20}\ N$

So, the required force is $1.98\times 10^{20}\ N$ .

3 0

3 years ago

When four people with a combined mass of 320 kg

ale4655 [162]

Each person is 80kg. 320/4

4 0

4 years ago

If 20 N force does 400 J<br> of work to move an<br> object, how far does the<br> object move?

Neporo4naja [7]

Answer:

Explanation:

W = F*d

400 = 20*d

d = 20

4 0

3 years ago