Answer:
m/s^2
Explanation:
Force = mass × acceleration
kgm/s^2 = kg × acceleration
where acceleration = Force ÷ mass
= kg m/s^2 ÷ kg
:Acceleration = m/s^2
Answer:
Id = 1/2 Md * R^2 = 1/2 * .1 * .1^2 = .0005 kg m^2 inertia of disk
Ib = Mb * R^2 = .02 * .1^2 = .0002 kg m^2 inertia of bug at edge
(Id + Ib) w1 = Id w2 conservation of angular momentum
w2 = .0007 / .0005 * 10 = 14 /sec angular speed with bug at center
KE1 = 1/2 I1 * w1^2 = 1/2 * .0007 * 10^2 = .035 kg m^2 / s^2
KE2 = 1/2 * I2 w2*2 = (.0005 / 2 ) ^ 14^2 = .049 kg m^2 / s^2
The bug has to exert radial force on the disk to maintain its
centripetal acceleration. As the bug crawls to the center of the disk it
does work against this centripetal force which appears as an increase
of rotational energy of the disk. As the the bug crawls back to the edge
of the disk, the disk does work on the bug and loses KE.
Answer: v = 20 m/s
Explanation: Solution:
Use the formula of Kinetic Energy and derive for v:
KE = 1/2 mv²
To find v:
v = √ 2 KE / m
= √ 2 ( 100000 J ) / 500 kg
= √ 400 m/s
= 20 m/s