Answer: Option (C) is the correct answer.
Explanation:
Formula for moment of inertia is as follows.
M.I = 
Hence, moment of inertia of two rods is as follows.
M.I of two rods = 
=
As third rod have no connection with vertices. So, moment of inertia of a rod along an axis passing through its center is as follows.
M.I = 
= 
= 
Using parallel axis theorem moment of inertia through vertices is as follows.


= 
h = 
Now, we will calculate the moment of inertia of third rod about vertices is as follows.
![\frac{mb^{2}}{36} + [(\frac{m}{3}) \times 3\frac{b^{2}}{4}]](https://tex.z-dn.net/?f=%5Cfrac%7Bmb%5E%7B2%7D%7D%7B36%7D%20%2B%20%5B%28%5Cfrac%7Bm%7D%7B3%7D%29%20%5Ctimes%203%5Cfrac%7Bb%5E%7B2%7D%7D%7B4%7D%5D)
= ![mb^{2}[\frac{1}{36} + \frac{1}{4}]](https://tex.z-dn.net/?f=mb%5E%7B2%7D%5B%5Cfrac%7B1%7D%7B36%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%5D)
= 5 
Therefore, total moment of inertia is calculated as follows.
Total M.I = 
= 
Thus, we can conclude that the moment of inertia of the wire triangle about an axis perpendicular to the plane of the triangle and passing through one of its vertices is
.
The mass of the fuel in the tank can be calculated by
multiplying the volume in full tank to the density of the gasoline. First
convert 22.3 gallons to ml by multiplying it with 3785.412 since the conversion
factor is 1 gallon= 3785.412 ml. Then multiply the volume with the density.
Since the density is in g/ml, you would get a value in grams so convert it to
kg by dividing it with 1000. The convert the value in kg to lb multiply the
value by 2.2. The values are 69.27 kg and 152.72 lb.
AMA- actual machine advantage
IMA- ideal / theoretical machine advantage
Efficiency = AMA / IMA
=3 / 10
=0.3
The different reflections of light through two separate mediums causes the bending of wave fronts associated with light rays. The reflection and refraction is caused by the medium associated with its light rays.