The better statistics that can be used to compare the scores of the two teams are: <u>D. Median and IQR.</u>
- The diagram given shows two box plots representing the data of the two team's scores.
<u><em>Box plots</em></u><u><em> displays the </em></u><u><em>5-number summary</em></u><u><em>, namely:</em></u>
- Minimum data value
- Maximum data value
- Median
- First Quartile
, and - Third Quartile
The Interquartile Range (IQR) of the data can also be calculated by finding the difference between the First Quartile , and the Third Quartile .
The Interquartile Range (IQR) helps us to determine the variability of the data set.
The median that is gotten from the box pot measures the center tendency of the data.
Both median and IQR are better statistics that can be easily gotten from box plots to compare the team scores.
Therefore, the better statistics to use for comparing the scores of the teams are: <u>D. Median and IQR.</u>
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Answer:
D) 3 units
Step-by-step explanation:
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Answer:
A
Step-by-step explanation:
as one number being added on both sides
Using the Pythagorean theorem we can solve for x.
x^2 + 6^2 = 10^2
Simplify:
x^2 + 36 = 100
Subtract 36 from both sides:
x^2 = 64
x = √64
x = 8
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
