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fiasKO [112]
3 years ago
9

-1/9 + (-5/9) write in simplest form

Mathematics
2 answers:
Snezhnost [94]3 years ago
6 0

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

ki77a [65]3 years ago
6 0

Answer:

-\frac{2}{3}

Step-by-step explanation:

-\frac{1}{9} + (-\frac{5}{9} )

Since you have two negative fractions you add them together and put a negative sign in front of the fraction.

1+5=6                                  so you have

-\frac{6}{9}                     Now you have to simplify 6 and 9 are both divisible by 3 so                             divide  both by 3 separately and then put it back in fraction form

-6÷3=-2

9÷3=3                    back in fraction form

-\frac{2}{3}                      You can't simplify any more so -\frac{2}{3} is your answer

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Find the area of the circle with the following dimension diameter = 4 cm
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Answer:

A = 12.56 cm^{2}

Step-by-step explanation:

<u>When you want to find area out of diameter. These are the steps you follow:</u>

1. Convert diameter to radius

2. Solve for area

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<u>First step:</u>

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3 years ago
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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 5.3

Identify the test scores that are significantly low or significantly high.

Significantly low

Z = -2 and lower.

So the significantly low scores are thoses values that are lower or equal than X when Z = -2. So

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 20.8}{5.3}

X - 20.8 = -2*5.3

X = 10.2

Test scores of 10.2 or lower are significantly low.

Significantly high

Z = 2 and higher.

So the significantly high scores are thoses values that are higherr or equal than X when Z = 2. So

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 20.8}{5.3}

X - 20.8 = 2*5.3

X = 31.4

Test scores of 31.4 or higher are significantly high.

3 0
3 years ago
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