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Eddi Din [679]
3 years ago
11

A random number generator is used to create a list of 200 single-digit numbers. Of those 200 numbers, 105 are even and ninety-fi

ve are odd. Seven was generated fifteen times. What is the experimental probability of an odd number other than seven being generated?
Mathematics
2 answers:
EastWind [94]3 years ago
5 0

Answer:

0.4 or 40%

Step-by-step explanation:

The total number of trials in this case is 200, since there were 200 single-digit numbers generated.

Of those 200, we know that 95 of them were odd.  Of the 95 odd numbers, seven was listed 15 times; this leaves us

95-15 = 80 odd numbers that were not the number 7.

This is 80 numbers out of a possible 200; this is 80/200, which simplifies to 40/100 = 0.4, which is the same as 40%.

Debora [2.8K]3 years ago
4 0
The answer is 40.0%. It is correct I seen the answer.
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Applying the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

<h3>How to Apply the Midpoint Formula?</h3>

The midpoint formula, which can be used in determining the coordinates of the midpoint between two endpoints is usually expressed as: M[(x1 + x2)/2, (y1 + y2)/2].

Given the following coordinates:

Midpoint of GH --> m(-13/2,-6) = (x, y)

One endpoint ---> G(-4, 1) = (x1, y1)

The other endpoint ---> (x2, y2)

Plug in the values into the formula used in calculating the midpoint:

m(-13/2,-6) = [(-4 + x2)/2, (1 + y2)/2]

Solve for x2

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y2 = -13

Thus, using the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

Learn more about the midpoint formula on:

brainly.com/question/13115533

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