When simplifying rational exponents like
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Check the picture below.
so notice, the sides AB and AC you can pretty much count them off the grid.
now, to get the CB side.
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) C&({{ -5}}\quad ,&{{ 1}})\quad % (c,d) B&({{ 3}}\quad ,&{{ -5}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ CB=\sqrt{[3-(-5)]^2+[-5-1]^2}\implies CB=\sqrt{(3+5)^2+(-5-1)^2} \\\\\\ CB=\sqrt{8^2+(-6)^2}\implies CB=\sqrt{100}\implies CB=10](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AC%26%28%7B%7B%20-5%7D%7D%5Cquad%20%2C%26%7B%7B%201%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AB%26%28%7B%7B%203%7D%7D%5Cquad%20%2C%26%7B%7B%20-5%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0ACB%3D%5Csqrt%7B%5B3-%28-5%29%5D%5E2%2B%5B-5-1%5D%5E2%7D%5Cimplies%20CB%3D%5Csqrt%7B%283%2B5%29%5E2%2B%28-5-1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0ACB%3D%5Csqrt%7B8%5E2%2B%28-6%29%5E2%7D%5Cimplies%20CB%3D%5Csqrt%7B100%7D%5Cimplies%20CB%3D10)
sum all three sides up, and that's the perimeter of the triangle.
so notice, the sides AB and AC you can pretty much count them off the grid.
now, to get the CB side.
sum all three sides up, and that's the perimeter of the triangle.