Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Each week, a cook purchased 12 LBS. of Butter:
During the Last year: (12 Months):
Cook Paid:
Little: $23.04
Much: $29.40, For Butter he or she purchased in a week:
Question: is: what is the Difference between, the Greatest price per pound, and the least price per pound of butter the cook paid within the last year?
EQUATION:
Least Paid / 12 =====> 23.04 /12
Most Paid / 12 ======> 29.40 / 12
Divide:
23.04 / 12 = 1.92 / LB
29.40 / 12 = 2.45 / LB
Now Subtract:
2.45 - 1.92
Answer ======> 0.53 is the difference, between the greatest price per round, and least price per round of butter the cook would have paid within the last year.
Hope that helps!!! : )
Answer:
-72
Step-by-step explanation:
Sum is adding so I just did substitution for this. 26+-72=-46 because a positive plus a negative equals a negative.
The value of a would be 3.5, as a=1 when b=10 means that a is worth 1/10 of b's value.
