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4 years ago

4,750 mm

Mathematics

1 answer:

raketka [301]4 years ago

4 0

Answer:

its b

Step-by-step explanation:

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Chan receives a bonus from his job. He pays 30% in taxes, gives 30% to charity, and uses another 15% to pay off an old debt. He

charle [14.2K]

Answer:

Chan's Bonus amount was $2400.

Step-by-step explanation:

Let the Total amount receive from bonus be 'x'.

Given:

Chan pays 30% in taxes;

So we can say;

Amount paid in taxes will be equal to 30% of total amount receive

framing in equation form we get;

Amount paid in taxes = $\frac{30}{100}x=0.3x = 0.3x$

Now Given:

Chan pays 30% in Charity;

So we can say;

Amount paid in charity will be equal to 30% of total amount receive.

framing in equation form we get;

Amount paid in Charity = $\frac{30}{100}x=0.3x$

Also Given:

Chan pays 30% in old debts;

So we can say;

Amount paid in Old debts will be equal 30% of total amount receive

framing in equation form we get;

Amount paid in Old debts = $\frac{15}{100}x=0.15x$

Money left with him = $600

Now we can say that Total Amount Receive in bonus will be equal to Amount paid in taxes plus Amount paid in charity plus Amount paid in old debts plus amount left.

framing in equation form we get;

$x=0.3x+0.3x+0.15x+600\\\\x= 0.75x +600\\\\x-0.75x=600\\\\0.25x=600\\\\x=\frac{600}{0.25} = \$2400$

Hence Chan's Bonus amount was $2400.

7 0

4 years ago

1/4x+13 > 1/4 (2x-32) multi step inequality

vlada-n [284]

Answer:

I belive it would be x<84

Step-by-step explanation:

please let me know if i am wrong

3 0

3 years ago

Read 2 more answers

7 · 15 can be written as _____. 5(7 + 10) 10(7 + 5) 7(10 + 5)

netineya [11]

For the answer to the question above,
An easy trick can be to just find the product of 15*7. Then with that product see which product equals to the ones written on the answer choices.

the answer is 7(10+5)
I hope my answer helped you.

8 0

4 years ago

Read 2 more answers

A graphing calculator is recommended. A crystal growth furnace is used in research to determine how best to manufacture crystals

Sophie [7]

Answer:

a) $w_1 = \frac{-2.156 -\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=-54.896$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=33.336$

And since the power can't be negative then the solution would be w = 33.34 watts.

b) $202= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-182=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-182)}}{2*0.1}=33.222$

$204= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-184=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-184)}}{2*0.1}=33.449$

So then the range of voltage would be between 33.22 W and 33.45 W.

c)For this case $\epsilon = \pm 1$ since that's the tolerance 1C

d) $\delta_1 =|33.222-33.336|=0.116$

$\delta_2 =|33.449-33.336|=0.113$

So then we select the smalles value on this case $\delta =0.113$

e) For this case if we assume a tolerance of $\epsilon=\pm 1C$ for the temperature and a tolerance for the power input $\delta =0.113$ we see that:

$lim_{x \to a} f(x) =L$

Where a = 33.34 W, f(x) represent the temperature, x represent the input power and L = 203C

Step-by-step explanation:

For this case we have the following function

$T(w)= 0.1 w^2 +2.156 w +20$

Where T represent the temperature in Celsius and w the power input in watts.

Part a

For this case we need to find the value of w that makes the temperature 203C, so we can set the following equation:

$203= 0.1w^2 +2.156 w +20$

And we can rewrite the expression like this:

$0.1w^2 +2.156 w-183=$

And we can solve this using the quadratic formula given by:

$w =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

Where a =0.1, b =2.156 and c=-183. If we replace we got:

$w_1 = \frac{-2.156 -\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=-54.896$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-183)}}{2*0.1}=33.336$

And since the power can't be negative then the solution would be w = 33.34 watts.

Part b

For this case we can find the values of w for the temperatures 203-1= 202C and 203+1 = 204 C. And we got this:

$202= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-182=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-182)}}{2*0.1}=33.222$

$204= 0.1w^2 +2.156 w +20$

$0.1w^2 +2.156 w-184=$

$w_2 = \frac{-2.156 +\sqrt{2.156^2 -4(0.1)(-184)}}{2*0.1}=33.449$

So then the range of voltage would be between 33.22 W and 33.45 W.

Part c

For this case $\epsilon = \pm 1$ since that's the tolerance 1C

Part d

For this case we can do this:

$\delta_1 =|33.222-33.336|=0.116$

$\delta_2 =|33.449-33.336|=0.113$

So then we select the smallest value on this case $\delta =0.113$

Part e

For this case if we assume a tolerance of $\epsilon=\pm 1C$ for the temperature and a tolerance for the power input $\delta =0.113$ we see that:

$lim_{x \to a} f(x) =L$

Where a = 33.34 W, f(x) represent the temperature, x represent the input power and L = 203C

8 0

4 years ago

What is 56 divided by 19

tresset_1 [31]

2.947368421 when dividing you want to make sure te numbers are divisible

5 0

4 years ago

Read 2 more answers