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mel-nik [20]
4 years ago
9

13.05 Completing the Square:

Mathematics
1 answer:
Afina-wow [57]4 years ago
6 0
The way these equations are arranged helps. 
First only deal with the left handside. 

<span>X^2+20x= (x+a)^2 -b where we are looking for a,b
You need to know the general formula for (x+a)^2=x^2+2ax+a^2
20x = 2*10x so a will be 10
(x+10)^2= x^2+20x+100

Now lets look at the original question: 
</span><span>X^2+20x=10
we know now that </span>(x+10)^2= x^2+20x+100
Thus X^2+20x=(x+10)^2 -100
So X^2+20x=10 becomes

(x+10)^2 -100 =10
(x+10)^2=110
For the other question you need to follow the same logic.
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What isbthe mean of the set of data 7 5 9 5 12
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Answer:

mean is the average set of Numbers

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mean = 7+5+9+5+12 all divided by 5

38/5

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In a random sample of n1 = 156 male Statistics students, there are x1 = 81 underclassmen. In a random sample of n2 = 320 female
Scilla [17]

Answer:

The p-value for the test of hypothesis is P(z<-3.617)=0.0002.

Step-by-step explanation:

Hypothesis test on the difference between proportions.

The claim is that the percent of males who are underclassmen stats students (π1) is less than the percent of females who are underclassmen stats students (π2).

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2

The male sample has a size n1=156. The sample proportion is p1=81/156=0.52.

The female sample has a size n2=221. The sample proportion in this case is p2=221/320=0.69.

The weigthed average of proportions p, needed to calculate the standard error, is:

p=\dfrac{n_1p_1+n_2p_2}{n_1+n_2}=\dfrac{81+221}{156+320}=\dfrac{302}{476}= 0.63

The standard error for the difference in proportions is:

\sigma_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.63*0.37}{156}+\dfrac{0.63*0.37}{320}}\\\\\\\sigma_{p1-p2}=\sqrt{\dfrac{0.2331}{156}+\dfrac{0.2331}{320}}=\sqrt{0.001503871+0.000728438}=\sqrt{0.002232308}\\\\\\\sigma_{p1-p2}=0.047

Then, we can calculate the z-statistic as:

z=\dfrac{p_1-p_2}{\sigma_{p1-p2}}=\dfrac{0.52-0.69}{0.047}=\dfrac{-0.17}{0.047}=-3.617

The P-value for this left tailed test is:

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