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2 years ago

What is an equivalent expression to 12a+6b

Mathematics

1 answer:

zhuklara [117]2 years ago

4 0

Answer:

3(4a + 2b)

Step-by-step explanation:

if we were to expand this back out then we would get 12a + 6b

3 x 4 = 12 then add the a (12a)

3 x 2 = 6 then add the b (6b)

then your plus sign and you have your original ancwer meaning that this problem is correct

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Use elimination to solve each system if equation 3x+2y=0and x-5y=17

kotykmax [81]

Answer:

$y = -3$

$x=2$

Step-by-step explanation:

$3x + 2y = 0$

$x - 5y=17$

to use the elimination you have to make one of the numbers same

$3(x-5y=17)$

and you would have to change the sign so that both of the 3x could cancel out.

New system of equation

$3x + 2y = 0$

$-3x+15y=-51$

$17y=-51$

$y = -3$

so we know the y value so now you could find the x value take one equation

$x - 5y=17$

$x +15=17$

$x = 2$

you could try it with both of the equations

$3x + 2y = 0$

$3x + - 6=0$

$3x-6=0$

$3x=6$

$x=6/3$

$x=2$

6 0

3 years ago

What is the reciprocal of 8 5/6

VashaNatasha [74]

475).)ggbbghffffrrffffffffffffffffff

4 0

3 years ago

Using the 3 functions below, make the desired transformation(s) to the correct function and describe the transformation(s). Writ

Eduardwww [97]

Answer:

The transformation of $g(x)$ to $k(x)$ consists in a vertical translation. The new equation is $k(x) = -12\cdot x-6$ .

Step-by-step explanation:

Let $g(x) = -12\cdot x - 3$ . We proceed to make the required transformations on $g(x)$ , which consists in one vertical translation, 3 units in the -y direction. That is to say:

$k(x) = g(x) - 3$ (1)

$k(x) = (-12\cdot x - 3) - 3$

$k(x) = -12\cdot x-6$

Then, the transformation of $g(x)$ to $k(x)$ consists in a vertical translation. The new equation is $k(x) = -12\cdot x-6$ .

5 0

2 years ago

How much higher is 500 than 400

DerKrebs [107]

99.9 is the answer is that ok

7 0

2 years ago

Read 2 more answers

What is 3x?

MissTica

Answer: 3 · 30= 90

Step-by-step explanation:

yes you are correct

6 0

3 years ago