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3 years ago

Can someone help me?

Mathematics

1 answer:

hoa [83]3 years ago

5 0

Answer:

Step-by-step explanation:

If arccos (√3 / 2) = β, then cos β = adjacent side / hypotenuse = √3 / 2. This tells us immediately that the adjacent side length is √3 and the hypotenuse is 2. Via the Pythagorean Theorem, we know that the third side is 1.

This information rules out the 1st and 3rd answer choices.

Because cos 30° = adj / hyp = √3 / 2, we can conclude that the correct answer is the 4th one: 30°, 60°, 90°

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Please help will mark brainiest

guapka [62]

Answer:

I think it is B, AB or CD and AB || CD

Step-by-step explanation:

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3 years ago

Which number line represents the solution set for the inequality 3(8-4x)<6(x-5)

quester [9]

Answer:

x>3

Step-by-step explanation:

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1 year ago

The owner of a small pet supply store wants to open a second store in another city, but he only wants to do so if more than one-

Andrei [34K]

Answer:

The answer is "The null hypothesis was rejected".

Step-by-step explanation:

Following are the right-tailed test:

Calculating the null and alternative hypothesis:

$H_0 : p = 0.3333\\\\H_a : p > 0.3333\\\\n = 150\\\\x = 64\\\\\hat{p} = \frac{x}{n} = \frac{64}{150} = 0.4267\\\\P_0 = 0.3333\\\\1 - P_0 = 1 - 0.3333 = 0.6667\\\\$

$z = \frac{\hat{p} - P_0}{[\sqrt{\frac{P_0 \times (1 - P_0 )}{n}}]}$

$= \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426$

Calculating the right-tailed test:

$P(z > 2.426) = 1 - P(z < 2.426) = 1 - 0.9924 = 0.0076\\\\P-value = 0.0076\\\\\alpha = 0.05\\\\P-value < \alpha$

Therefore, we reject the null hypothesis.

This example shows that more than a third of the families own pets in this town.

5 0

2 years ago

Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank's water are poured out. how many gallons of water are left in th

Advocard [28]

Answer:

Water left in tank is $3\frac{1}{6}$ gallons.

Step-by-step explanation:

Given :

Capacity of tank = 9.5 gallons $=\frac{95}{10}$

Water taken out of tank = $6\frac{1}{3}=\frac{19}{3}$ gallons

We have to find the water left in the tank.

Water left in the tank = Total capacity of tank - water taken out of tank

= $\frac{95}{10}-\frac{19}{3}$

Taking LCM of (3,10)= 30

$\Rightarrow \frac{95 \times 3-19 \times10}{30}$

Solving further, we get,

$\Rightarrow \frac{285-190}{30}$

$\Rightarrow \frac{95}{30}=\frac{19}{6}=3\frac{1}{6}$

Thus, Water left in tank is $3\frac{1}{6}$ gallons..

5 0

3 years ago

Read 2 more answers

F(x)=|x-5|+2 Evaluate f(3). A.) 10 B.) 0 C.) 4 D.) 6

Talja [164]

F(x)=|x-5|+2
plug it in

so f(3)
f3)=|3-5|+2
solve whats inside first
|-2|+2
since its absolute value its actually positive
2+2
4

Your answer is C.) 4

4 0

3 years ago