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qwelly [4]
4 years ago
10

What is the 5th term in the sequence b(n)=-1(2)^n-1

Mathematics
1 answer:
vladimir2022 [97]4 years ago
8 0

-16

i fot it from khan

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KengaRu [80]

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0^2 +(y-3)^2 = 25

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Step-by-step explanation:

For this cae we have the following functon given:

x^2 +(y-3)^2 = 25

And we want to find the coordinate axes so then we can do the following:

If x=0 we have:

0^2 +(y-3)^2 = 25

(y-3)^2= 25

y-3= \pm 5

y_1 = 5+3=8

y_2 = -5+3=-2

Now of y =0 we have:

x^2 +9 = 25

x^2 = 16

x= \pm 4

And then the coordinate axes are:

(4,0) (-4,0), (0,8), (0,-2)

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3 years ago
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