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3 years ago

12

70 days=?Weeks Hey guess if u help me I will help u thx

2 answers:

pentagon [3]3 years ago

8 0

There are 7 days a week, so you would divide 70÷7 which equals 10. Therefore the answer is 10 weeks :)

hjlf3 years ago

6 0

The answer is 10 weeks

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one day in october, agent sanchez enters the code 3477 how do you know this is code is incorrect and and will not open the door

kozerog [31]

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2 years ago

What is the standard form equation of an ellipse that has vertices (−2,14) and (−2,−12) and co-vertices (9,1) and (−13,1)?

Gennadij [26K]

Answer:

$\frac{(x+2)^2}{121} + \frac{(y-1)^2}{169} = 1$

Step-by-step explanation:

First, we identify that the vertices are vertical.
(an image below is attached if you want to see a visualization)
Therefore, the equation is such:

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1$

(h,k) is the center of the ellipse, which we could easily calculate by finding the midpoint between any pair of vertices.

This gets us (-2, 1)

Therefore, h = -2, k = 1

Now we want to find a,

we know the length of the major axis is 2a, and in this case, our length of the major axis is 26. So a = 13

Now we want to find b,

We know the length of the minor axis is 2b, and in this case, our length is 22, so b = 11

Now we will just plug in all the values and simplify to get our answer! B)

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2 years ago

What property of equality is x=x

Vaselesa [24]

Answer: I think its all real numbers

Step-by-step explanation:

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4 years ago

I WILL GIVE THE BRAINLEST HURRY PLEASE

alina1380 [7]

Answer:

B) 6

Step-by-step explanation:

It is 45, 45, 90 degrees right triangle, the ratio of the triangle 1:1:√2

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Thank you.

4 0

4 years ago

Read 2 more answers

Calculate the area under the graph of f(x) = 1/xlnx from x = e to x = e^e

Gnom [1K]

Using integration, it is found that the area under the graph of f(x) in the desired interval is of 1 unit squared.

<h3>How is the area under a graph found?</h3>

The area under the graph of a curve f(x) between x = a and x = b is given by the following integral:

$A = \int_{a}^{b} f(x) dx$

In this problem, the function and the limits of integration are given by:

$f(x) = \frac{1}{x\ln{x}}$

$a = e, b = e^e$

Hence:

$A = \int_{e}^{e^e} \frac{1}{x\ln{x}} dx$

Using substitution:

$u = \ln{x}$

$du = \frac{1}{x} dx$

$dx = x du$

Hence:

$\int \frac{1}{x\ln{x}} dx = \int \frac{1}{u} du = \ln{u} = \ln{\ln{x}}$

Applying the Fundamental Theorem of Calculus:

$A = \ln{\ln{e^e}} - \ln{\ln{e}} = \ln{e\ln{e}} = \ln{\ln{e}} = \ln{e} - \ln{1} = 1$

Hence, the area under the graph of f(x) in the desired interval is of 1 unit squared.

To learn more about integration, you can take a look at brainly.com/question/20733870

7 0

3 years ago