Dont solve just find the system of equations

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

3y + x = 6

4y + 1.50x = 8.50

Step-by-step explanation:

Cost of walnut = $1.50

Cost of cashew = $1.00

Cost of dates = $1.50

Let

Dates = x

Cashew = y

Walnuts = 2y

Pounds of total mixture = 6 lb

Total cost of the mixture = $8.50

First equation (from Quantity)

Walnuts + cashew + dates = Total mixture

2y + y + x = 6

3y + x = 6

Second equation (from price× Quantity)

2y(1.50) + y(1.00) + x(1.50) = 8.50

3y + y + 1.50x = 8.50

4y + 1.50x = 8.50

Therefore, the system of equation to solve the question is

3y + x = 6

4y + 1.50x = 8.50

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The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is

saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

α = 0.05, α/2 = 0.025

From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

t =T.INV.2T(0.05, 128) = 2.34

Taking the positive value of t, we get

Confidence interval is ,

$\overline X \pm t \times \frac{s}{\sqrt n}$

$34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

(32.52, 35.8)

95% confidence interval is (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.