Answer:
4948.01
Step-by-step explanation:
You do pi*radius squared *height to get the volume.
Hope this helps.
Answer is 10(2k+5)
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Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
3x - 4 < = 2
3x < = 2 + 4
3x < = 6
x < = 6/3
x < = 2
2x + 11 > = -1
2x > = -1 - 11
2x > = -12
x > = -12/2
x > = -6
however, since ur inequality has " or " instead of " and " .....ur answer I believe is going to be {x | x < = 2}
Answer:
23,230
Step-by-step explanation:
230 is ten times larger than 23, and if you add them together is it 253
If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
