You count each unit square and it counts as one so for number two from point o to point a there are 5 unitsif each side we’re 5 hints and there are 6 sides you multiply five by six to get the answer of 39 for number three
China could expect a quantity of visitors of 8.512 × 10⁶ in Chicago.
<h3>How to apply direct proportions</h3>
A <em>direct</em> proportion is a <em>direct</em> relationship between two variables, which in this case is represented between the quantity of tourists in the city of Chicago and the population of the country of origin.
Let suppose the existence of direct proportionality and world has a population of 9000 million people, the quantity of Chinese visitors in the city of Chicago is determined by the following formula:
x = (1.393 × 10⁹ / 9 × 10⁹) × 55 × 10⁶
x = 8.512 × 10⁶
China could expect a quantity of visitors of 8.512 × 10⁶ in Chicago. 
To learn more on direct proportions, we kindly invite to check this verified question: brainly.com/question/14389660
100
explanation: those two angles are supplementary which add up to be 180.
Answer:
c is correct have a nice day
Step-by-step explanation:
Answer:
<h3>#1</h3>
The normal overlaps with the diameter, so it passes through the center.
<u>Let's find the center of the circle:</u>
- x² + y² + 2gx + 2fy + c = 0
- (x + g)² + (y + f)² = c + g² + f²
<u>The center is:</u>
<u>Since the line passes through (-g, -f) the equation of the line becomes:</u>
- p(-g) + p(-f) + r = 0
- r = p(g + f)
This is the required condition
<h3>#2</h3>
Rewrite equations and find centers and radius of both circles.
<u>Circle 1</u>
- x² + y² + 2ax + c² = 0
- (x + a)² + y² = a² - c²
- The center is (-a, 0) and radius is √(a² - c²)
<u>Circle 2</u>
- x² + y² + 2by + c² = 0
- x² + (y + b)² = b² - c²
- The center is (0, -b) and radius is √(b² - c²)
<u>The distance between two centers is same as sum of the radius of them:</u>
<u>Sum of radiuses:</u>
<u>Since they are same we have:</u>
- √(a² + b²) = √(a² - c²) + √(b² - c²)
<u>Square both sides:</u>
- a² + b² = a² - c² + b² - c² + 2√(a² - c²)(b² - c²)
- 2c² = 2√(a² - c²)(b² - c²)
<u>Square both sides:</u>
- c⁴ = (a² - c²)(b² - c²)
- c⁴ = a²b² - a²c² - b²c² + c⁴
- a²c² + b²c² = a²b²
<u>Divide both sides by a²b²c²:</u>
Proved