To answer the question above, let x be the shorter one of the pieces. With the variable, we can express the longer piece as 2x + 3. Based on the given, the sum of the lengths of these pieces should sum up to 14 ft.
2x + 3 + x = 14 ft, x = 3 2/3 ft
Substituting this value for the longer piece, we get 10 1/3 ft. Thus, the lengths of the pieces are 3 2/3 ft and 10 1/3 ft.
The whole is 10/10 (consider to use the same denominator when comparing fractions) The half of 10/10 will be 5/10 which is not 4/10.
it's close to half but not the half
when x= -4 ,f(x)=2
Step-by-step explanation:
the coordinate in which f(x) i.e y=2 is (-4,2)
thus x= -4
Answer:
x = 2.25 y = 0.75
Step-by-step explanation:
2x = 9.5- 5
2x = 4.5
x = 4.5 ÷ 2
x = 2.25
know we now what is x so in the second one we evaluate x
3(2.25) + 5y = 10.5
6.75 + 5y = 10.5
5y = 10.5- 6.75
5y = 3.75
y = 3.75 ÷ 5
y = 0.75
that's it !
if you want to check your answer you can evaluate x and y so it will be like
2×2.25 + 5
= 4.5 + 5 = 9.5
and
3× 2.25 +5×0.75
= 6.75 + 3.75 = 10.5
Answer:
a. 5% of the employees will experience lost-time accidents in both years
b. 24% of the employees will suffer at least one lost-time accident over the two-year period
Step-by-step explanation:
a. What percentage of the employees will experience lost-time accidents in both years?
20% last year, of those who suffered last year, 25% during this year. So
5% of the employees will experience lost-time accidents in both years.
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
5% during the two years.
10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.
First year yes, not on the second.
75% of 20%. So, total:
24% of the employees will suffer at least one lost-time accident over the two-year period