Question

In slope-intercept form, what is the equation of the line passing through the points (−2, 19) and (5, −9)? y = −4x − 11 y = −4x + 11 y = −4x + 3

Answer 1

For this case we have that the slope of a line is given by:

$m = \frac {y2-y1} {x2-x1}$

We have the following points:

$(x1, y1) = (- 2,19)\\(x2, y2) = (5, -9)$

Substituting:

$m = \frac {-9-19} {5 - (- 2)}\\m = \frac {-28} {5 + 2}\\m = \frac {-28} {7}\\m = -4$

Thus, the slope-intercept form equation is given by:

$y = -4x + b$

We substitute any of the points to find the cut point with the y axis.

$-9 = -4 (5) + b\\-9 = -20 + b\\b = -9 + 20\\b = 11$

So, we have:

$y = -4x + 11$

Answer:

Option B

Answer 2

Answer:

y = -4x + 11

Step-by-step explanation: