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babunello [35]
3 years ago
6

Art and his friends spent $62 at the movies. Admission tickets cost $12 apiece, and a bucket of popcorn costs $7. Which equation

written in standard form represents the number of tickets bought, t, and the number of buckets of popcorn bought, p?
A)12p + 7t = 62
B)7p + 12t = 62
C)12p = 62 – 7t
D)7p = 62 – 12t
Mathematics
2 answers:
Yanka [14]3 years ago
8 0

Answer:

on edg the answer is B

Step-by-step explanation:

i just took the test and got a 100

Korvikt [17]3 years ago
6 0

The right answer is Option B: 7p+12t=62

Step-by-step explanation:

Given,

Amount spent by Art and his friends = $62

Cost of one ticket = $12

Cost of t tickets = 12t

Cost of one bucket of popcorn = $7

Cost of p buckets of popcorn =7p

According to given statement;

7p+12t=62

7p+12t=62 represents the number of tickets bought, t, and the number of buckets of popcorn bought, p.

The right answer is Option B: 7p+12t=62

Keywords: addition, linear equation

Learn more about linear equations at:

  • brainly.com/question/1903425
  • brainly.com/question/1878521

#LearnwithBrainly

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What mathematical pattern can be seen in a perfect square trinomial and how is the pattern used to factor the trinomi
Shtirlitz [24]
(a ± b)² = a² ± 2ab + b² . . . . . . . (signs match)

The middle term is twice the product of the roots of the other two terms. This tells you the terms of the binomial are the square roots of the end terms.

The sign in the binomial will match the sign of the "2ab" term. The order of terms in the binomial doesn't matter. (a±b)² = (b±a)² when signs match.
8 0
4 years ago
J^2 over 2j times 2j over 3g
Serhud [2]

Answer:

D

Step-by-step explanation:

given \frac{j^2}{2j} × \frac{2j}{3g}

the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as

= \frac{j^2}{3g} → D


5 0
3 years ago
Aidan is participating in an 8 mile walk for his favorite charity. The organizers used a coordinate grid to plot the course. The
Travka [436]

Answer:

Aidan is 2 miles far from the ending point when he reaches the water station.

Step-by-step explanation:

The locations of the starting point, water station and ending point are (3, 1), (3, 7) and (3, 9), all expressed in miles. First we determine the distances between starting and ending points and between starting point and water station by the Pythagorean Theorem:

From starting point to ending point:

D = \sqrt{(3-3)^{2}+(9-1)^{2}} (Eq. 1)

D = 8\,mi

From starting point to water station:

d = \sqrt{(3-3)^{2}+(7-1)^{2}} (Eq. 2)

d = 6\,mi

The distance between the water station and the ending point is:

s = D-d (Eq. 3)

s = 8\,mi-6\,mi

s = 2\,mi

Hence, Aidan is 2 miles far from the ending point when he reaches the water station.

3 0
3 years ago
Hii help I to lazy to do it
Oksanka [162]

Answer:

3 cans

Step-by-step explanation:

We need to find the area of the deck

A = 9 1/9 * 3

Changing to an improper fraction

9 1/9 = (9*9+1)/9 = 82/9

A = 82/9 *3 = 82/3

Changing back to  a mixed number

82/3 = 27  1/3

Each can covers 10 m^2

We will need 3 cans

3 0
3 years ago
Read 2 more answers
What is the value of x?<br><br><br><br> Enter your answer in the box.
Grace [21]
The shapes are similar.
When two figures are similar, the ratios of the lengths of their corresponding sides are equal.
Therefore,
\frac{42}{(15 + 42)} = \frac{x}{10 + x}

Simplify:
\frac{42}{57} = \frac{x}{10 + x}
Cross multiply:
42(10+x) = 57x
420 + 42x = 57x
420 = 57x - 42x
420 = 15x
x = (420÷15)
x = 28

3 0
3 years ago
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