Answer:
Speed of boat in still water = 64 km/hr
Speed of the current = 11 km/hr
Step-by-step explanation:
Let the speed of motorboat in still water = x km/hr
Let the speed of current = y km/hr
Motorboat travels 371 km in 7 hours going upstream.
Speed of motorboat while going upstream = speed of motorboat in still water - speed of current = (x-y)
=> ![\[x-y = \frac{371}{7}\]](https://tex.z-dn.net/?f=%5C%5Bx-y%20%3D%20%5Cfrac%7B371%7D%7B7%7D%5C%5D)
=>
------------------------------(1)
Motorboat travels 525 km in 7 hours going downstream.
Speed of motorboat while going downstream = speed of motorboat in still water + speed of current = (x+y)
=> ![\[x+y = \frac{525}{7}\]](https://tex.z-dn.net/?f=%5C%5Bx%2By%20%3D%20%5Cfrac%7B525%7D%7B7%7D%5C%5D)
=>
-----------------------------(2)
Solving for x and y from (1) and (2):
Adding (1) and (2):
2x = 128
=> x = 64
Substituting the value of x in (1), y = 11
Answer:
8. 
9. -38 ÷ 19
10. -4 ÷ -2
11. 190° im pretty sure
Step-by-step explanation:
We start with

Assuming that
we can cross multiply the equation:

You can recognize the perfect square pattern in the quadratic equation:

So, we have

Which is the only solution, with multiplicity 2.
1 hour = 60 minutes.
Convert the minutes to decimals by diving by 60
30/60 = 0.5
2 hours and 30 minutes = 2.5 hours
45/60 = 0.75
5 hours 45 minutes = 5.75 hours
15/50 = 0.25
3 hours 15 minutes = 3.25 hours
Ow add all the hours:
2.5 + 5 + 5.75 + 3.25 = 16.5 hours
Answer: B. 16.50