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3 years ago

5

Aidan is participating in an 8 mile walk for his favorite charity. The organizers used a coordinate grid to plot the course. The

starting point is at (3,1) and the ending point is at (3,9). At (3,7), there's a water station to make sure the walkers stay hydrated. How far along will Aidan be in the walk when he reaches the water station?

1 answer:

Travka [436]3 years ago

3 0

Answer:

Aidan is 2 miles far from the ending point when he reaches the water station.

Step-by-step explanation:

The locations of the starting point, water station and ending point are (3, 1), (3, 7) and (3, 9), all expressed in miles. First we determine the distances between starting and ending points and between starting point and water station by the Pythagorean Theorem:

From starting point to ending point:

$D = \sqrt{(3-3)^{2}+(9-1)^{2}}$ (Eq. 1)

$D = 8\,mi$

From starting point to water station:

$d = \sqrt{(3-3)^{2}+(7-1)^{2}}$ (Eq. 2)

$d = 6\,mi$

The distance between the water station and the ending point is:

$s = D-d$ (Eq. 3)

$s = 8\,mi-6\,mi$

$s = 2\,mi$

Hence, Aidan is 2 miles far from the ending point when he reaches the water station.

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Answer:

h(1)=-13

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Step-by-step explanation:

We are given that

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$h(2)=-13-13=-26=h(1)-13$

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$h(3)=-13(3)=-39=-26-13=h(2)-13$

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$h(n)=h(n-1)-13$

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h(1)=-13

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Answer:

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$BC = \sqrt{110}$

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$CA = \sqrt{98}$

Now we all the sidelengths:

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