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frozen [14]
3 years ago
5

Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a

whole number of dollars, How many bagels did she buy?
Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0
3.75  ,,,,,,,,,,,,,,,,,,
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A baseball team wants to collect at least 160 cans of food for an upcoming food drive. Team members brought 42 cans of food on M
Irina18 [472]
If they collect 65 on Monday, 42 on Wednesday and the rest on Friday, then we can write it down as:

65 + 42 + x ≥ 160
107 + x ≥ 160                 / - 107 (both sides)
x ≥ 53

So the team needs to collect at least 53 cans on Friday.
4 0
3 years ago
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A taxi charges $2 for the first fifth of a mile and $0.25 for each additional fifth of a mile. What is the cost of a 2-mile ride
Svet_ta [14]

I believe the answer is $6.

7 0
3 years ago
Please help... I will mark the right answer brainiest
Luda [366]

Answer:

the answer is 3725

Step-by-step explanation:

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6 0
3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
234 divided by 33 I really need this answer doing school work
Elodia [21]

Answer:

7.0909090909 hope this helps!!

4 0
3 years ago
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