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2 years ago

Describe how to find the sums -4+2 and -4+(-2) on a number line.

2 answers:

6 0

Answer: Make a number line. Start at 0. For -4+2 you go back 4 on a number line. Then you add 2. You will end up on -2. For -4+(-2) you start at 0. You go back 4 until you reach -4, then you go back another 2. You should end up on -6.

kifflom [539]2 years ago

3 0

For -4+2, plot -4, then move to the right 2 spaces. You should land on -2.

For -4+(-2), plot -4 then move the left 2 spaces. You should land on -6.

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Jamie owns about 3 times as much books as Carly. Jamie owns 42 books write an equation and use it to estimate the number n of bo

Marina CMI [18]

Answer:

Carly owns 14 books.

Step-by-step explanation:

42/3= 14

hope this helps!!! (:

4 0

2 years ago

Which of the following is not a similarity transformation?

Degger [83]

I think its shear, because that is the only one in which the shape actually changes shape and size

7 0

2 years ago

Read 2 more answers

After which value of x does function g exceed function f?

uysha [10]

Say this: "after x=2, g(x) exceeds f(x). Note that for x=3, g(3) > f(3). Check that out.

3 0

3 years ago

Place the numbers 0 to 8, inclusive, in the magic square so that the sum of the numbers in each row, column, and diagonal is the

ehidna [41]

Answer: See attached table

Step-by-step explanation:

$\begin{table}[]\begin{tabular}{lllll} & & & & \\ & & & & \\ & & & & \\ & & & & \end{tabular}\end{table}$ +---+---+---+

| 1 | 8 | 2 |

+---+---+---+

| 6 | 4 | 2 |

+---+---+---+

| 5 | 0 | 7 |

+---+---+---+

<u>Proofs:</u>
First row: 1+6+5 = 12

Second row: 8+4+0 = 12

Third row: 2+2+7 = 12

First column: 1+8+2 = 12

Second column: 6+4+2 = 12

Third column: 5+0+7 = 12

Diagonal starting from top left to bottom right: 1+4+7 = 12

Diagonal staring from top right to bottom left: 2+4+5 = 12

6 0

2 years ago

For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?

irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is $\frac{2x^2+8x}{(x+4)(x^2-9)}$

To find for what value of x is undefined in the given expression :

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}$

$=\frac{2x}{x^2-9}$

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}$

If we put x=3 in the above expression we get

$\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}$

$=\frac{6}{9-9}$

$=\frac{6}{0}$

Therefore $\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}$

The value at x =3 is undefined for the given expression

7 0

3 years ago