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3 years ago

Find the Highest Common Factor (HCF) of 196 and 12

Mathematics

2 answers:

Norma-Jean [14]3 years ago

7 0

Answer:

The greatest common factor is 4

Step-by-step explanation:

1.Find the prime factorization of 12

a) 12 = 2 × 2 × 3

2.Find the prime factorization of 196

a) 196 = 2 × 2 × 7 × 7

To find the GCF, multiply all the prime factors common to both numbers:

a)GCF=2x2

Therefore, GCF = 2 × 2

GCF = 4

Yakvenalex [24]3 years ago

6 0

this is from google, and i think it has the answer that you need.

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Please help, I'm going crazy on this question ;(

maksim [4K]

Step-by-step explanation:

Hey!

So mode is basically the most occurring number in the given data.

So first arrange it in ascending or descending order.

so it will be- 1,1,2,2,3,7

Here the most frequently occurring is 1 and 2

so mode=1,2

7 0

3 years ago

Read 2 more answers

A scientist begins with 250 grams of a radioactive substance. After 250 minutes, the sample has decayed to 32 grams. Rounding to

s2008m [1.1K]

Answer:

Part 1 : $A=250 e^{-0.008223t}$

Part 2 : Half life is 84 minutes ( approx )

Step-by-step explanation:

Part 1 : Suppose the function that shows the amount( in grams ) of the substance after t minutes,

$A=A_0 e^{kt}$

If t = 0 min, A = 250 grams,

$250=A_0 e^{0}$

$\implies A_0 = 250$

If t = 250, A = 32 grams,

$32 = A_0 e^{250k}$

$32 = 250 e^{250k}$

$0.128 = e^{250k}$

Taking ln both sides,

$\ln(0.128) = 250k$

$\implies k =\frac{\ln(0.128)}{250}=-0.008223$

Hence, the equation that shows this situation,

$A=250 e^{-0.008223t}$

Part 2 : If A = 250/2 = 125,

$125 = 250 e^{-0.008223t}$

$0.5 = e^{-0.008223t}$

Taking ln both sides,

$\ln(0.5) = -0.008223t$

$\implies t =\frac{\ln(0.5)}{-0.008223}\approx 84$

Therefore, the half life of the substance would be 84 minutes.

8 0

3 years ago

Evaluate. 15 + 102 • [12 – (12 – 3 • 2)] + 6

mylen [45]

Answer:

633

Step-by-step explanation:

We have the equation

$15+102[12-(12-3*2)]+6\\\\15+102[12-(12-6)]+6\\\\15+102[12-(6)]+6\\\\15+102[6]+6\\\\15+612+6\\\\633$

3 0

3 years ago

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Which polygons are congruent? Select <img src="https://tex.z-dn.net/?f=%5Cbold%7Beach%7D" id="TexFormula1" title="\bold{

gregori [183]

<h3>Answer: Everything but the lower right hand corner</h3>

==============================

Explanation:

Notice for the corners mentioned, we have the figures with corresponding angles that are the same (shown by similar arc markings) and they have congruent corresponding sides as well (aka they are the same length shown by similar tickmarks). Rotating one figure has it transform into the other.

The only time this does not happen is with the pair of figures in the bottom right hand corner. One square has side lengths of 20, the other has side lengths of 25. The two figures are not congruent due to the side mismatch.

8 0

3 years ago

How to simplify -3 (4×-5y-5×)

VMariaS [17]

Distribute -3 to the rest of the numbers by multiplying them together. That’s all you need to do you don’t have to solve

6 0

3 years ago

Read 2 more answers