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Serjik [45]
3 years ago
7

A triangle has an area of 16 square feet.The height is 8 feet. What is the length of the base

Mathematics
2 answers:
arsen [322]3 years ago
8 0
4 is the base because the formula for a triangle is base times height divided by two, you would know that 8 times 4 would equal 32. When divided by 2 it would equal 16 which is the area. So 4 is the answer.
Reptile [31]3 years ago
7 0
Hello! 
==
Well, What can 8 be multiplied by to get 16?
==
8x8= 16, so the length is going to be 8!
==
Hope this helps! :) Please mark brainliest!
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there are 90 people in a group. 6 of the people are men. The number of women is 2 times the number of men. the rest are children
stepladder [879]

Answer:

n= 12

Step-by-step explanation:

6*2= 12

Men= 6

Women= 12

12+6= 18

90-18= 72

72:6= 12:1

3 0
3 years ago
Explain 3 1/5 *5/8 i need an explanation or i wont get full marks
Sholpan [36]
3/1= 3.87500 8


Simplify 5/8
<span>31over 5 x 5 over 8 = 31/8


answer </span>3/1= 3.87500 8
5 0
3 years ago
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What is pythagoras triplets?
dedylja [7]
A pythagoras triplet is a set of three numbers ... not just any three numbers,
but a set where the (square of one of them) is the sum of the (squares of the
other two). 

If they're related in that way, then they can be the lengths of the sides of a
right triangle.

If they're not, then they can't.
5 0
3 years ago
Simplify -4(3-1)+2 <br><br>​
nikdorinn [45]

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses.

-4(3 - 1) + 2

3 - 1 = 2

-4(2) + 2

We have no exponents so go on to multiplication

-4(2) + 2

-4 * 2 = -8

-8 + 2

No division so go to addition

-8 + 2

When adding a positive number with a negative number you will act as if you are subtracting the two numbers, then take the sign of the largest number  (disregarding the signs). In this case the largest number is 8 and its sign is negative. Your answer will have a negative sign.

-6

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
4 years ago
For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
3 years ago
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