Answer:
100°
Step-by-step explanation:
A triangle is a polygon shape with three sides. Triangles are of different types such as obtuse, scalene, equilateral, isosceles etc.
In triangle ABC:
70° + 50° + ∠C = 180° (sum of angles in a triangle)
120 + ∠C = 180
∠C = 180 - 120
∠C = 60°
Since ∠C is bisected into ∠ACD and ∠BCD, hence:
∠ACD = ∠BCD = ∠C / 2
∠ACD = ∠BCD = 60 / 2
∠ACD = ∠BCD = 30°
In triangle ACD:
∠A + ∠ACD + ∠ADC = 180° (sum of angles in a triangle)
50 + 30 + ∠ADC = 180
∠ADC + 80 = 180
∠ADC = 100°
Answer:
21°
Step-by-step explanation:
set it up
7x-1+3x-9=180
combine like terms
10x-10=180
take the ten to the other side
10x=190
divide both sides by 10
x=19
plug x in
3(10)-9
30-9
21
(Incase you need it the other angle is 159°)
Answer:
12x9y9
Step-by-step explanation:
( 4x3y3 ) 3
= 4x ⋅ 3 ⋅ 3y ⋅ 3 ⋅ 3 ⋅ 3
= 12x9y9
See attachment file below.
Answer: 11/3
Hope it helped!
Answer:
<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>
Step-by-step explanation:
In triangle DEF, we have:
<u>Given</u>:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
<u>Proof</u>: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)
