To make a frequency table, you will need to find the lowest and highest average number of movies.
Numbers go from 0.5 to 4.5.
And example of frequencies you could use are:
0-0.9 (1)
1-1.9(5)
2-2.9(5)
3-3.9(2)
4-4.9(1)
The frequencies are in parentheses beside the intervals.
Answer:
False, they take form of a U shape
Answer:
62$
Step-by-step explanation:
FORGET THEM IM SAVING MY MONEY
The area of the triangle is
A = (xy)/2
Also,
sqrt(x^2 + y^2) = 19
We solve this for y.
x^2 + y^2 = 361
y^2 = 361 - x^2
y = sqrt(361 - x^2)
Now we substitute this expression for y in the area equation.
A = (1/2)(x)(sqrt(361 - x^2))
A = (1/2)(x)(361 - x^2)^(1/2)
We take the derivative of A with respect to x.
dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]
dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]
dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]
Now we set the derivative equal to zero.
(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0
-2x^2 + 361 = 0
-2x^2 = -361
2x^2 = 361
x^2 = 361/2
x = 19/sqrt(2)
x^2 + y^2 = 361
(19/sqrt(2))^2 + y^2 = 361
361/2 + y^2 = 361
y^2 = 361/2
y = 19/sqrt(2)
We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
Since 18 does not have a number that when multiplied by itself equal 18, then it will be a decimal number. You can tell the closest whole number by seeing what is the closest square. In this case we know that 16 is 4 times 4 and the next one would be 5 times 5 to equal 25, so the whole number would be 4.
Now, the easiest way to do this is to get you calculator and take the square root of 18 to get 4.242641. The problem wants it to be to the nearest tenth so 4.2 is your answer. On a number line, if it is in four parts, you will plot it just before the first little line.
Hope this helps! If you are using more small lines in you number line, comment me below and I would be happy to lead you in the right direction.
