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kirill115 [55]
3 years ago
7

PLEASE HELP ASAP!!

Mathematics
1 answer:
Temka [501]3 years ago
5 0
By definition we have to:
 Difference of squares of two terms is equal to the product of the sum of these terms by the difference of these terms:
 a ^ 2 - b ^ 2 = (a + b) (a - b)

 We then have the following expression:
 y^ 2-225

 Rewriting we have:
 y^ 2-15 ^ 2

 Using the definition, we have to:
 y ^ 2-15 ^ 2 = (y-15) * (y + 15)

 Answer:
 
B: is a difference of squares: (y-15)(y+15)
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On the face of it, [5.3%, 8.65%].

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If you mean that up to 8.65% may be added to the base 5.3% rate, then the total can be in the range [5.3%, 13.95%].
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Each of the 25 balls in a certain box is either red, blue or white and has a number from 1 to 10 painted on it. If one ball is t
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Answer:

Not sufficient information

Step-by-step explanation:

Probability of white ball: P(W)

Probability of even number: P(E)

Probability of white ball or even number: P(W∨E) is asked

Considering case (1):

Probability of white ball and even number: P(W∧E) = 0

And we know that,

P(W∨E) = P(W) + P(E) - P(W∧E) = P(W) + P(E) - 0 = P(W) + P(E)

It is not sufficient to calculate the desired probability.

Considering case (2):

P(W) - P(E) = 0.2

Here, it is possible for P(W) and P(E) to get multiply values.

So P(W∨E) cannot be determined.

Considering cases (1) & (2):

P(W∧E) = 0 and P(W) - P(E) = 0.2

So, P(W∨E) = P(W) + P(E) = P(E) + 0.2 + P(E) = 2P(E) + 0.2

Again multiple answers are possible.

Such as, for P(E) = 0.4 (10 even balls) ⇒ P(W∨E) = 1

but for P(E) = 0.2 (5 even balls) ⇒ P(W∨E) = 0.6

So, the information are not sufficient.

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3 years ago
There are 12 crayons in a box. How many boxes will be needed for 8 children if each child gets 7 crayons?
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Each child gets =7×8=56crayoms

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Total boxes

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Round to next whole as we can't have depict

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