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3 years ago

Complete the square. Fill in the number that makes the polynomial a perfect-square quadratic. 2 + 2) +

1 answer:

7 0

Try using either the app the calculater not like those other ones this calculator can solve fractions and almost any other thing

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Solve for x. x= In e x=

IgorLugansk [536]

Good morning ☕️

Answer:

x = 1

Step-by-step explanation:

since the function ln is the inverse of the function exponential then :

$ln(e )=lne^{1} = 1$

3 0

3 years ago

8 km b 17 km What is the length of the missing leg?

Bond [772]

The answer is 15.

17^2-8^2=225
sr of 225= 15
:))

7 0

3 years ago

Solve 5z(z+2)(z−1)=0.

fredd [130]

Answer:

if you are solving for z it is:

Step-by-step explanation:

z=0,-2,1

5 0

3 years ago

Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th

xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is $\bold{W=-3e^{7x}}$

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

$W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|$

Thus replacing the functions of the exercise we get:

$W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|$

Working with the determinant we get

$W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}$

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0

3 years ago

Can someone please help

Juliette [100K]

Answer:

201.06

Step-by-step explanation:

3.14 * 8^2= 201.06

(pi * radius ^ squared)

5 0

3 years ago

Read 2 more answers

Complete the square. Fill in the number that makes the polynomial a perfect-square quadratic. 2 + 2) +​

Complete the square. Fill in the number that makes the polynomial a perfect-square quadratic. 2 + 2) +