All categories

4 years ago

An equation is shown below:

2 answers:

8 0

5 (2×-8)+15= -15

distribute the 5 into (2×-8) and it becomes

10x-40 + 15 = -15

add -40 and +15

10× - 25 = -15

add +25 to both sides

10x= 10

divide both sides by 10

x = 1

Tasya [4]4 years ago

5 0

5(2x-8)+15=-15 -15 in both sides 5(2x-8)=-30 /5 2x-8=-6 +8 2x=2 /2 x=1 I hope it helps

You might be interested in

Mr. Parker asked his students to draw and label a solid figure. He gave these directions: . Use two rectangular prisms e The vol

Anastaziya [24]

jkaa[kakskskawz82xb2b2jdw

6 0

3 years ago

Angel is driving home from a vacation. She is 400 miles from home. She drives an average rate of 50 mph until she gets home. Wri

Debora [2.8K]

Angel is driving home from a vacation. She is 400 miles from home. She drives an average rate of 50 mph until she gets home. Write a function for this situation and then graph your function the function for this situation can be solve using d = rt

Where d is the distance, r is the velocity and t is time

So the function d(t) = 50t

5 0

3 years ago

A wall in Marcus's bedroom is 8 1/3 feet high and 16 1/5 feet long. If he paints 1/3 of the wall blue, how many square feet will

Andreyy89

8 1/3=25/3

16 1/5=81/5

25/3*81/5=135

1/3 of 135=45 sq ft

4 0

3 years ago

Prove that the points (a, -3a), (2a, a) and (0, -2a) form a scalene trqingle

Dmitry [639]

Answer:

See below.

Step-by-step explanation:

Remember that a scalene triangle has lengths of different values.

Therefore, we just need to find the length or <em>distance</em> from each point to the next. If the three distances we acquire are different, then we prove that the point do indeed form a scalene triangle.

Let's let A be (a, -3a), B be (2a, a), and C be (0, -2a).

So, let's find each of the side lengths using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Side AB:

Let's let A:(a, -3a) be (x₁, y₁) and let's let B:(2a, a) be (x₂, y₂). Substitute this into our formula:

$d=\sqrt{(2a-a)^2+(a-(-3a))^2$

Subtract:

$d=\sqrt{(a)^2+(4a)^2$

Square:

$d=\sqrt{a^2+16a^2}$

Add:

$d=\sqrt{17a^2}$

Simplify:

$d=\sqrt{a^2}\cdot \sqrt{17}\\d=|a|\sqrt{17}$

So:

$\overline {AB}=|a|\sqrt{17}$

Note: We need the absolute value because anything squared will be positive, and if you take the square root of something positive, the result will be positive. The absolute value ensures that the a value will be positive no matter what a is to begin with.

Side BC:

Let's let C:(0, -2a) be (x₁, y₁) and let's let B:(2a, a) be (x₂, y₂).

$d=\sqrt{(2a-0)^2+(a-(-2a)^2}$

Subtract:

$d=\sqrt{(2a)^2+(3a)^2}$

Square:

$d=\sqrt{4a^2+9a^2}$

Add:

$d=\sqrt{13a^2}$

Simplify:

$d=\sqrt{a^2}\cdot \sqrt{13}\\d=|a|\sqrt{13}$

Therefore:

$\overline{BC}=|a|\sqrt{13}$

Side AC:

Let's let A:(a, -3a) be (x₁, y₁) and let's let C:(0, -2a) be (x₂, y₂).

$d=\sqrt{(0-a)^2+(-2a-(-3a))^2$

Subtract:

$d=\sqrt{(-a)^2+(a)^2}$

Square:

$d=\sqrt{a^2+a^2}$

Add:

$d=\sqrt{2a^2}$

Simplify:

$d=|a|\sqrt2$

Therefore:

$\overline{AC}=|a|\sqrt2$

So, our three side lengths are:

$\overline {AB}=|a|\sqrt{17}\text{, }\overline{BC}=|a|\sqrt{13}\text{, and } \overline{AC}=|a|\sqrt2$

We can see that the three side lengths are different since they do not equal to same thing.

Therefore, we can deduce that the triangle must be scalene.

And we're done!

4 0

3 years ago

Read 2 more answers

Lily deposited $500 in a savings account. At the end of 1 year, she had earned $20 in simple interest. What interest rate did sh

Vlad1618 [11]

Hi! To find the amount of simple interest earned, we can divide the amount earned in interest by the amount in the savings account. 20/500 is 0.04. To get this in percent form, multiply by 100 to get 4. Lily's savings account received an interest rate of 4%.

7 0

3 years ago