How do I find the midpoint of a segment ?
2 answers:
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For the largest area, half the fence is used parallel to the river, and the other half is used for the two ends of the rectangular space.
The dimensions are 475 m by 237.5 m.
_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.
The dimensions are 475 m by 237.5 m.
_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.
Option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively. This can be obtained by knowing what similar triangles are and finding which sides are proportional.
<h3>Find the correct option:</h3>Similar triangles: If two triangles have proportional sides the are similar.
For example, if ΔABC and ΔDEF are similar then
∠ABC = ∠DEF and ∠ACB = ∠DFE
Then we can write that, ΔABC ~ ΔDEF
Here in this question,
Since A, Y, Z are midpoints of sides XW, VW, XV
XA = AW
WY = VY
XZ = VZ
To consider sides AY and XV we should take triangles ΔWAY and ΔWXV
(since A is the midpoint of WX)
(since Y is the midpoint of WV)
∠AWY = ∠XWV (reflexive property)
Therefore ΔWAY and ΔWXV are similar triangles
= 2
∠WAY = ∠WXV and ∠AYW = ∠XVW
Hence,
AY || XV option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively.
Learn more about similar triangle here:
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Analyze the diagram below and answer the question that follows. If Z, Y and A are midpoints of ΔVWX what is true about AY and XY?
A. AY || XV
B. 1/2 AY = XV
C. AY = XV
D. AY ≅ XV
Answer:
Step-by-step explanation: