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zhenek [66]
3 years ago
8

Find the value of X

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0
The answer is x equals 17
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2x-3y=9 Find the x- and y-intercepts and graph the equation plotting the intercepts. Please show all of your work.
Llana [10]
To find where graph is intercepting x and y axis all we have to do is to calculate what is value of x when y = 0 (x intercept) and what value of y is when x = 0 (y intercept)

1)   x = 0
-3y = 9
y = -3

2)  y = 0
x = 9/2

Graph is bellow.

8 0
3 years ago
Jeffrey earned $65 doing yard work. He bought a pair of jeans for $31.25 and a sweatshirt for $16.50.He set aside the money left
koban [17]

Answer:

$17.25

Step-by-step explanation:

Jeffrey earned $65 doing yard work.

He bought a pair of jeans costs = $31.25

and a sweatshirt costs = $16.50

Total amount he spent = 31.25 + 16.50 = $47.75

Now he left with money from his shopping = $65.00 - $47.75

= $17.25

Jeffrey set aside $17.25 for the gift.

3 0
3 years ago
Which equation represents a line that passes through (2, –) and has a slope of 3?
jok3333 [9.3K]
Y - (-1/2) = 3(x - 2)
y + 1/2 = 3(x - 2)
6 0
3 years ago
Please help me with this problem ! I would appreciate it
marta [7]
Area of triangle: 1/2(base)(height)
Area of rectangle: length × width

Find the area of the triangles on the sides first using 1/2(base)(height).
Plug 8 for the base and 6 for the height.

1/2(8)(6) = 24 units²
Multiply 24 by 2 for both of the triangles.
(24)(2) = 48 units²

Find the area of the rectangles of the object using length × width.
For the rectangle on top, you can find the width using the Pythagorean Theorem: a² + b² = c².

Plug in 6 and 8 for a and b, and find c (width).
6² + 8² = c²
36 + 64 = 100
Square root both sides; √100 = 10.
The width of the rectangle on top is 10.

Now plug 20 for the length and 10 for the width.
20 × 10 = 200 units²

For the rectangle on the bottom, plug in 20 for the length and 8 for the width.
20 × 8 = 160 units²

For the rectangle on the side, plug in 20 for the length and 6 for the width.
20 × 6 = 120 units²

Add up all the areas ⇒ 48 + 200 + 160 + 120 = 528 units².
4 0
4 years ago
From the top of a 6m house, the angle of elvation to the top of a flappole is across the street is 9 degrees. the angle of depre
Anuta_ua [19.1K]

The height of the flag pole which is described as in the task content is; 8.2m.

<h3>What is the height of the flagpole as described from the top of the 6m house?</h3>

The horizontal distance between the 6m house and the flagpole in discuss can be evaluated by means of the angle of depression and trigonometric identity, tan as follows;

tan 22° = 6/x

x = 6/tan 22 = 14.9m.

Consequently, the horizontal distance from the top of the house to the top of the flagpole is therefore;

tan 9° = y/14.9

y = 14.9 tan 9° = 2.2m

Ultimately, the height of the flagpole is; 6+2.2 = 8.2m.

Read more on trigonometric identities;

brainly.com/question/24349828

#SPJ1

5 0
2 years ago
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