We have two unknowns: x and y. Now, we have to formulate 2 equations. The first would come from the use of the given ratio:

We use the distance formula to find the distance between coordinates:

3/4 = √[(x-4)²+(y-1)²] / √[(4-12)²+(1-5)²]
√[(x-4)²+(y-1)²] = 3√5
(x-4)²+(y-1)² = 45
x² - 8x + 16 + y² - 2y + 1 = 45
x² - 8x + y² - 2y = 28 --> eqn 1

The second equation must come from the equation of a line:
y = mx +b
m = (5-1)/(12-4) = 1/2

Substitute y=5 and x=12 for point (12,5)
5 = (1/2)(12) + b
b = -1

So, the second equation is

y = 1/2x -1 or x = 2 + 2y --> eqn 2

Solving the equations simultaneously:
(2 + 2y)² - 8(2 + 2y) + y² - 2y = 28
Solving for y,
y = -2
x = 2+2(-2) = -2

Therefore, the coordinates of point A is (-2,-2).

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3 years ago

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Simplify the following (x-y)²

Elanso [62]

Answer:

$x^{2} -2xy+y^{2} \$