I don’t think I’m doing the top correctly. Could you help 7-10?

Mathematics

1 answer:

natta225 [31]3 years ago

8 0

a trapezoid

equation for area = h(a +b) ÷ 2

so you sub that in

8(9 +21) ÷ 2 = 8 × 30 ÷ 2 = 120

so the area is 120cm

A trapezoid

equation for area = h(a +b) ÷ 2

so you sub that in

6(9 + 5 ) ÷ 2 = 6 × 14 ÷ 2 = 42

So the answer is 42 inches

A kite

equation for area = p× q ÷ 2

so you sub that in

(3+3)×(4.5+6.5) ÷ 2 = 6×11÷2 = 3

So the answer is 33 cm

sorry I can't see 10s measurements

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What is the equation of a line parallel to y=1/2×+6 that passes through (-4,1)

IgorC [24]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

$(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3$