Step-by-step explanation:
The problem statement says λ<1. If this is true, then the cannonball is slower than the boat, and it will never reach the boat. So I assume it's actually λ>1.
If we say t is the amount of time, then the boat travels south a distance of ut, and the cannonball travels a distance of λut.
v = λut
ut = v/λ
Using Pythagorean theorem:
d² + (ut)² > v²
d² + (v/λ)² > v²
λ²d² + v² > λ²v²
λ²d² > (λ² − 1) v²
λ² / (λ² − 1) > (v/d)²
Answer:
3a-3b-5c
Step-by-step explanation:
((3a-3b)²-(5c)²)÷(3a-3b+5c)=((3a-3b-5c)(3a-3b+5c))÷(3a-3b+5c)=3a-3b-5c
The answer to this one is<em> xy + 4</em>
Answer:
150 + 1.5d
Step-by-step explanation:
increase 120 by d%
d% = d/100
So, increasing 120 by d % means
120 + (d/100 * 120)
= 120 + 1.2d
Then increase this by 25%
= (120 + 1.2d) + 25/100(120 + 1.2d)
= 120 + 1.2d + (120+1.2d)/4
= 120 + 1.2d + 30 + 0.3d
= 120 + 30 + 1.2d + 0.3d
= 150 + 1.5d