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son4ous [18]
3 years ago
9

8 -2 — 3p4 What is equivalent to the expression?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

8 -2 =6

Step-by-step explanation:

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Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (1, 5).
Lesechka [4]

Answer:

4x-y+1=0

Step-by-step explanation:

here,given equation of a line id

4x-y-2=0.. eqn(i)

equation of any line parallel to line (i) is

4x-y+k=0...eqn(ii)

since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]

4*1-5+k=0

or, 4-5+k=0

or,-1+k=0

•°•k=1

substituting the value of k=1 in eqn(ii),

4x-y+1=0 is the required equation of the line.

4 0
3 years ago
9a+b-8c-2(a+3b-c) simplified
alekssr [168]

Answer:

The correct simplified answer for 9a + b - 8c - 2 (a + 3b - c) would be 7a - 5b - 6c

Step-by-step explanation:

Hope this helps! Sorry if there is no explanation, I am kinda in a rush.

5 0
3 years ago
Read 2 more answers
The line with x-intercept of 10 and y-<br> intercept of -2.
Yuri [45]

Answer:

y = \frac{1}{5} x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ = x- intercept (10, 0) and (x₂, y₂ ) = y- intercept (0, - 2)

m = \frac{-2-0}{0-10} = \frac{-2}{-10} = \frac{1}{5}

The y- intercept c = - 2

y = \frac{1}{5} x - 2 ← equation of line

8 0
3 years ago
Looking at the two quadratic functions below (1 &amp; 2), answer the following questions.
algol [13]
Part A:

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that parabola (2) is stretched horizontally by a factor of 13 which is greater than 1. This means that parabola (2) is further away from the x-axis than parabola (1). (i.e. parabola (2) is more 'vertical' than parabola (1).

Therefore, parabola (1) is wider than parabola (2).



Part B:

A parabola open up when the coefficient of the quadratic term (the squared term) is positive and opens down when the coefficient of the quadratic term is negative.

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that the coefficient of the quadratic term is positive for parabola (2) and negative for parabola (1), therefore, the parabola that will open down is parabola (1).



Part C:

For any function, f(x), the graph of the function is moved p places to the left when p is added to x (i.e. f(x + p)) and moves p places to the right when p is subtracted from x (i.e. f(x - p)).

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that in parabola (1), 12 is added to x, which means that the graph of the parent function is shifted 12 places to the left while in parabola (2), 4 is subtracted from x, which means that the graph of the parent function is shifted 4 places to the right.

Therefore, the parabola that would be furthest left on the x-axis is parabola (1).



Part D:

For any function, f(x), the graph of the function is moved q places up when q is added to the function (i.e. f(x) + q) and moves q places down when q is subtracted from the function (i.e. f(x) - q).

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that in parabola (2), 1 is added to the function, which means that the graph of the parent function is shifted 1 place up while in parabola (1), 6 is subtracted from the function, which means that the graph of the parent function is shifted 6 places down.

Therefore, the parabola that would be highest on the y-axis is parabola (2).
7 0
4 years ago
A hexagon has a radius measuring 23 cm. What is the approximate area of the hexagon?
attashe74 [19]
1374.4 square cm is the correct answer
7 0
3 years ago
Read 2 more answers
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