Answer:
The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.
This means that 
What proportion of childrenin this age range between 70 lbs and 85 lbs.
This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So
X = 85



has a pvalue of 1
X = 70



has a pvalue of 0.0694
1 - 0.0694 = 0.9306
The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.
Answer:The equation of the parabola is y=18(x−2)2−3
Answer:
x=3/2,1
Step-by-step explanation:Given
(3x-2)ˆ5-(3x-2)ˆ2=0
(3x-2)ˆ3(3x-2)ˆ2-(3x-2)ˆ2=0
(3x-2)ˆ2{(3x-2)ˆ3-1}=0
(3x-2)ˆ2=0 Or (3x-2)ˆ3-1=0
3x-2=0 Or(3x-2)ˆ3=1
x=3/2 Or 3x-2=1, x=1
Answer:
= 29.82 yards/second
Step-by-step explanation:
The speed is given in the problem. We just need to convert its units. The multiplicative identity (that is, 1) may be used to change the units without changing the value. (note: do you know what the additive identity is?)
61 miles per hour
(61 miles) / (1 hour)
(61 miles)/(1 hour)*1
((61 miles)/(1 hour))*((5280 feet)/(1 mile))
((61 miles)/(1 hour))*((5280 feet)/(1 mile))*((1 yard)/(3 feet))*((1 hour)/(60 minutes))*((1 minute)/(60 seconds))
note: miles, feet, hours, minutes cancel out; leaving yards per second
(61/1)*(5280/1)*(1/3)*(1/60)*(1/60) yards/second (note: I write that way to paste into Excel)