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Vitek1552 [10]
3 years ago
14

An antelope can run a speed of 61 miles per hour. What is this speed in yards per second? Round to the nearest hundredth

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

= 29.82 yards/second

Step-by-step explanation:

The speed is given in the problem.  We just need to convert its units.  The multiplicative identity (that is, 1) may be used to change the units without changing the value.  (note:  do you know what the additive identity is?)

     61 miles per hour

    (61 miles) / (1 hour)

   (61 miles)/(1 hour)*1

   ((61 miles)/(1 hour))*((5280 feet)/(1 mile))

   ((61 miles)/(1 hour))*((5280 feet)/(1 mile))*((1 yard)/(3 feet))*((1 hour)/(60 minutes))*((1 minute)/(60 seconds))

      note:  miles, feet, hours, minutes cancel out; leaving yards per second

    (61/1)*(5280/1)*(1/3)*(1/60)*(1/60)   yards/second          (note: I write that way to paste into Excel)

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Solve 5x ≥ 25. Graph the solution.
Zina [86]

Answer:

Step-by-step explanation:

Alright so we are going to solve

5x ≥ 25  Divide both sides by 5

x≥5

4 0
3 years ago
A right triangle has a hypotenuse length of 12, and one side length of 9. find the missing side length. do the side lengths form
Rina8888 [55]

Use the Pythagorean theorem:

a^2+b^2=c^2

c - a hypotenuse

a, b - legs

We have: a = 9 and c = 12. Substitute:

9^2+b^2=12^2

81+b^2=144               <em>subtract 81 from both sides</em>

b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}

A Pythagorean triple consists of three positive integers a, b and c, such that

a^2+b^2=c^2.

b=3\sqrt{7} is not positive integer.

<h3>The sides of the triangle do not form a pythagorean triple.</h3>
5 0
3 years ago
A explanation also would be super helpful and very appreciated!
xxTIMURxx [149]

Answer:

26%

Step-by-step explanation:

345. 24 - 274 = 71.24

71.24 / 274 =0.26

0.26 * 100 = 26

8 0
3 years ago
Help please!posted picture of question
Evgen [1.6K]
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)

The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)

Answer: The system of inequalities would produce the region indicated on the graph is Option B

8 0
3 years ago
A cube has a volume of greater than 123 cm3. What are the possible lengths of the side of that cube?
horrorfan [7]
When we cube root 123, we get a decimal which rounds out to 4.97. So possible side lengths would be any number greater than that.<span />
4 0
3 years ago
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