3 years ago

I really don’t understand this please help!!

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

H=√d^2-w^2
=√146.4 1-92.16
=7.3 inches
the principle used here is pythagoras theorem
all the best.

You might be interested in

Which of the following scatterplots would have a trend line with a positive slope?

labwork [276]

Answer:a

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Please someone help me

hram777 [196]

The answer is 57 inches

5 0

3 years ago

I need help with this!

Colt1911 [192]

The answer is 30 units

8 0

3 years ago

Segment FG begins at point F(-2, 4) and ends at point G (-2, -3). Segment FG is translated by (x, y) → (x – 3, y + 2) and then r

Mariana [72]

Answer:

The length of the segment F'G' is 7.

Step-by-step explanation:

From Linear Algebra we define reflection across the y-axis as follows:

$(x',y')=(-x, y)$ , $\forall\, x, y\in \mathbb{R}$ (Eq. 1)

In addition, we get this translation formula from the statement of the problem:

$(x',y') =(x-3,y+2)$ , $\forall \,x,y\in \mathbb{R}$ (Eq. 2)

Where:

$(x, y)$ - Original point, dimensionless.

$(x', y')$ - Transformed point, dimensionless.

If we know that $F(x,y) = (-2, 4)$ and $G(x,y) = (-2,-3)$ , then we proceed to make all needed operations:

Translation

$F''(x,y) = (-2-3,4+2)$

$F''(x,y) = (-5,6)$

$G''(x,y) = (-2-3,-3+2)$

$G''(x,y) = (-5,-1)$

Reflection

$F'(x,y) = (5, 6)$

$G'(x,y) = (5,-1)$

Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:

$F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}$

$F'G' = 7$

The length of the segment F'G' is 7.

8 0

3 years ago

⚠️⚠️⚠️help⚠️⚠️⚠️⚠️⚠️

Naddika [18.5K]

The second one should be the answer

7 0

3 years ago

Read 2 more answers