How much heat in joules is required to heat a 43g sample of aluminum from an initial temperature of 72˚F to a final temperature

Question

QveST [7]

4 years ago

9

How much heat in joules is required to heat a 43g sample of aluminum from an initial temperature of 72˚F to a final temperature

of 145˚F ?
Special heat capacity for aluminum is 0.903 J/g˚C

Chemistry

1 answer:

Stels [109] · Answer 1 · 2022-01-25T21:30:28+03:00

The first step to answering this item is to convert the given temperatures in °F to °C through the equation,

°C = (°F - 32)(5/9)

initial temperature: 72°F

  °C = (72 - 32)(5/9) = 22.22°C

final temperature: 145°F

  °C = (145 - 32)(5/9) = 62.78°C

Substituting to the equation,

H = mcpdT

H = (43 g)(0.903 J/g°C)(62.78 - 22.22)

H = 1574.82 J

<em>Answer: 1574.82 J</em>